Another way to see the stream of 1/37 spins.

If 15 repeats are average over spins 11-40; 30 spins. That average is 1-3-5-7=16, so, an even distribution would be 5-5-5=15

You see the 1st 10 spins had the repeat. The placement of the expected 15 non-hits, placed in 5’s.

Shows the non-hit are -2. The 12th non-hit highlighted brown.

The next 10 spins countback has 19 of the starting 37. It will need 7 of the 10 spins to be one of the remaining 25 non-hits.

The average to hit for non-hit is 2 spins; the 13th non-hit is late already, already gone 3 spins.